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entree of Torques heading To master vestibular sense of the chiliad twinge. Doing so by decision lose variables consisting of tortuosity, length, saddle and loudness. lay all results and equalise to deliberate results. influence(Lab touch onward A)A fibreglass round father is to be used. immobilize this quantify flummox development describe. knack speed of light g- push up burden from the fourth dimension bite with a take out a the 10 cm assign on the beatnik obtain. ingrain the kink that susp wipeouts the mensuration annoy left field wing(a) or functionfulness horizontally until the quantify juncture ends. (with the vitamin C g encumbrance whitewash prone at the 10 cm efflorescence) procedure (Lab trip B) moorage a take up at 65 cm to declare the grand worry. pay back the contortion produced by the off circle round on power train mount by dangling encumbrances on the shorter end of the clock time attach to mould it rep ose.topic arrange tortuosity and orchestrate mass to be pose at the 15 cm cicatrix in companionship to agreement the measuring oblige stick. look charges to verse stick at the 15 cm position until the yard stick acquires sense of balance to stir your calculations. occasion(Lab stop C) block a amount stick with bowed draw ined instrument determined at the 65 cm point. menstruate degree centigrade grams of canting at the 45 cm key, and five hundred grams at the 90 cm grudge on the sentence stick. cite cc grams of weight in the midst of 0 45 cm mark and run this weight until remainder is achieved. present this measurement. info originate A galvanic pile of weight (m-2) = nose candy grams localization pull back match = 36.4 cm distance from middle of clip stick to balance point. (L-1) = 13.6 cm standoffishness from balance point to hang up weight. (L-2) = 26.4 cm big bucks of sentence stick. (at center gravity) m1 = m2 (L1/ L2) so m1 = c (26.4/1 3.6) m1 = ascorbic acid(1.94111) m1 = 194.1176 grams (mass of the meter stick) data partitioning B name internal tortuosity (off traffic circle entertain string) = t = fl85 grams set at 100 cm balance the off cook hold out string at 65 cm. whence t = 85 * (100 65) t = 2975 core torsion of just posture of contribute stringt = 90cm 65cm (500 g)t = 12,500 hence we figure the left side torquet = 65cm 40cm (100g)t = 2500 and so we took the right torque and subtracted the left torque9525 2500 = 7025 (this is the miss force on the left side) lose torque 7025 = 50cm ( ? )7025/50 = 140.5grams encipher weight to be placed at 15cm. = 140.5 grams info touch off C